1304241010321 has 2 divisors, whose sum is σ = 1304241010322. Its totient is φ = 1304241010320.

The previous prime is 1304241010301. The next prime is 1304241010337. The reversal of 1304241010321 is 1230101424031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1264365313600 + 39875696721 = 1124440^2 + 199689^2 .

It is a cyclic number.

It is not a de Polignac number, because 1304241010321 - 2³¹ = 1302093526673 is a prime.

It is a super-2 number, since 2×1304241010321² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1304241010292 and 1304241010301.

It is not a weakly prime, because it can be changed into another prime (1304241010301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652120505160 + 652120505161.

It is an arithmetic number, because the mean of its divisors is an integer number (652120505161).

Almost surely, 2^{1304241010321} is an apocalyptic number.

It is an amenable number.

1304241010321 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304241010321 is an equidigital number, since it uses as much as digits as its factorization.

1304241010321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 1304241010321 its reverse (1230101424031), we get a palindrome (2534342434352).

The spelling of 1304241010321 in words is "one trillion, three hundred four billion, two hundred forty-one million, ten thousand, three hundred twenty-one".