Base | Representation |
---|---|
bin | 10010111110101010111… |
… | …010011101011000010111 |
3 | 11121200110220102220220011 |
4 | 102332222322131120113 |
5 | 132332042042321403 |
6 | 2435054420021051 |
7 | 163141226455654 |
oct | 22765272353027 |
9 | 4550426386804 |
10 | 1304242542103 |
11 | 463142a05936 |
12 | 190930231787 |
13 | 95cb3049a97 |
14 | 471a8bd6c2b |
15 | 23dd6609a6d |
hex | 12faae9d617 |
1304242542103 has 16 divisors (see below), whose sum is σ = 1332083413440. Its totient is φ = 1276524797184.
The previous prime is 1304242542101. The next prime is 1304242542121. The reversal of 1304242542103 is 3012452424031.
It is a cyclic number.
It is not a de Polignac number, because 1304242542103 - 21 = 1304242542101 is a prime.
It is a super-3 number, since 3×13042425421033 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1304242542101) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 42317763 + ... + 42348571.
It is an arithmetic number, because the mean of its divisors is an integer number (83255213340).
Almost surely, 21304242542103 is an apocalyptic number.
1304242542103 is a deficient number, since it is larger than the sum of its proper divisors (27840871337).
1304242542103 is a wasteful number, since it uses less digits than its factorization.
1304242542103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32778.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 1304242542103 its reverse (3012452424031), we get a palindrome (4316694966134).
The spelling of 1304242542103 in words is "one trillion, three hundred four billion, two hundred forty-two million, five hundred forty-two thousand, one hundred three".
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