Base | Representation |
---|---|
bin | 111100101110111110… |
… | …0010111010010100011 |
3 | 110110122112212210010021 |
4 | 1321131330113102203 |
5 | 4114102312432003 |
6 | 135525543014311 |
7 | 12265025155636 |
oct | 1713574272243 |
9 | 413575783107 |
10 | 130425124003 |
11 | 50349645089 |
12 | 2133b13a397 |
13 | c3b6ca18b5 |
14 | 6453b2dc1d |
15 | 35d533b2bd |
hex | 1e5df174a3 |
130425124003 has 2 divisors, whose sum is σ = 130425124004. Its totient is φ = 130425124002.
The previous prime is 130425123991. The next prime is 130425124013. The reversal of 130425124003 is 300421524031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130425124003 is a prime.
It is not a weakly prime, because it can be changed into another prime (130425124013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65212562001 + 65212562002.
It is an arithmetic number, because the mean of its divisors is an integer number (65212562002).
Almost surely, 2130425124003 is an apocalyptic number.
130425124003 is a deficient number, since it is larger than the sum of its proper divisors (1).
130425124003 is an equidigital number, since it uses as much as digits as its factorization.
130425124003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 130425124003 its reverse (300421524031), we get a palindrome (430846648034).
The spelling of 130425124003 in words is "one hundred thirty billion, four hundred twenty-five million, one hundred twenty-four thousand, three".
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