Base | Representation |
---|---|
bin | 111100101110111110… |
… | …1001000011110001011 |
3 | 110110122120021000110022 |
4 | 1321131331020132023 |
5 | 4114102340403301 |
6 | 135525551211055 |
7 | 12265026655151 |
oct | 1713575103613 |
9 | 413576230408 |
10 | 130425325451 |
11 | 50349772473 |
12 | 2133b216a8b |
13 | c3b70424b5 |
14 | 6453b833d1 |
15 | 35d537ad1b |
hex | 1e5df4878b |
130425325451 has 4 divisors (see below), whose sum is σ = 130427510472. Its totient is φ = 130423140432.
The previous prime is 130425325403. The next prime is 130425325463. The reversal of 130425325451 is 154523524031.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 154523524031 = 139 ⋅1111680029.
It is a cyclic number.
It is not a de Polignac number, because 130425325451 - 214 = 130425309067 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130425321451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1000385 + ... + 1123218.
It is an arithmetic number, because the mean of its divisors is an integer number (32606877618).
Almost surely, 2130425325451 is an apocalyptic number.
130425325451 is a deficient number, since it is larger than the sum of its proper divisors (2185021).
130425325451 is an equidigital number, since it uses as much as digits as its factorization.
130425325451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2185020.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 130425325451 its reverse (154523524031), we get a palindrome (284948849482).
The spelling of 130425325451 in words is "one hundred thirty billion, four hundred twenty-five million, three hundred twenty-five thousand, four hundred fifty-one".
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