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130425325451 = 614172123603
BaseRepresentation
bin111100101110111110…
…1001000011110001011
3110110122120021000110022
41321131331020132023
54114102340403301
6135525551211055
712265026655151
oct1713575103613
9413576230408
10130425325451
1150349772473
122133b216a8b
13c3b70424b5
146453b833d1
1535d537ad1b
hex1e5df4878b

130425325451 has 4 divisors (see below), whose sum is σ = 130427510472. Its totient is φ = 130423140432.

The previous prime is 130425325403. The next prime is 130425325463. The reversal of 130425325451 is 154523524031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 154523524031 = 1391111680029.

It is a cyclic number.

It is not a de Polignac number, because 130425325451 - 214 = 130425309067 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130425321451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1000385 + ... + 1123218.

It is an arithmetic number, because the mean of its divisors is an integer number (32606877618).

Almost surely, 2130425325451 is an apocalyptic number.

130425325451 is a deficient number, since it is larger than the sum of its proper divisors (2185021).

130425325451 is an equidigital number, since it uses as much as digits as its factorization.

130425325451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2185020.

The product of its (nonzero) digits is 72000, while the sum is 35.

Adding to 130425325451 its reverse (154523524031), we get a palindrome (284948849482).

The spelling of 130425325451 in words is "one hundred thirty billion, four hundred twenty-five million, three hundred twenty-five thousand, four hundred fifty-one".

Divisors: 1 61417 2123603 130425325451