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130430553401 is a prime number
BaseRepresentation
bin111100101111001000…
…1000100110100111001
3110110122221002121212002
41321132101010310321
54114110210202101
6135530255230345
712265122261041
oct1713621046471
9413587077762
10130430553401
1150351713295
1221340b183b5
13c3b8152c65
146454744721
1535d5a5ed6b
hex1e5e444d39

130430553401 has 2 divisors, whose sum is σ = 130430553402. Its totient is φ = 130430553400.

The previous prime is 130430553299. The next prime is 130430553431. The reversal of 130430553401 is 104355034031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82863379600 + 47567173801 = 287860^2 + 218099^2 .

It is a cyclic number.

It is not a de Polignac number, because 130430553401 - 222 = 130426359097 is a prime.

It is a super-2 number, since 2×1304305534012 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130430553431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65215276700 + 65215276701.

It is an arithmetic number, because the mean of its divisors is an integer number (65215276701).

Almost surely, 2130430553401 is an apocalyptic number.

It is an amenable number.

130430553401 is a deficient number, since it is larger than the sum of its proper divisors (1).

130430553401 is an equidigital number, since it uses as much as digits as its factorization.

130430553401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10800, while the sum is 29.

Adding to 130430553401 its reverse (104355034031), we get a palindrome (234785587432).

The spelling of 130430553401 in words is "one hundred thirty billion, four hundred thirty million, five hundred fifty-three thousand, four hundred one".