Base | Representation |
---|---|
bin | 1011110111001101010010… |
… | …1001100011110101011011 |
3 | 1201011220111020212210000002 |
4 | 2331303110221203311123 |
5 | 3202144221111001011 |
6 | 43423525002003215 |
7 | 2514221613632333 |
oct | 275632451436533 |
9 | 51156436783002 |
10 | 13043088375131 |
11 | 41795a739a781 |
12 | 1567a07aa650b |
13 | 737c5b825689 |
14 | 3314088420c3 |
15 | 17943236cc3b |
hex | bdcd4a63d5b |
13043088375131 has 2 divisors, whose sum is σ = 13043088375132. Its totient is φ = 13043088375130.
The previous prime is 13043088375049. The next prime is 13043088375143. The reversal of 13043088375131 is 13157388034031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13043088375131 is a prime.
It is a super-2 number, since 2×130430883751312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13043088377131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521544187565 + 6521544187566.
It is an arithmetic number, because the mean of its divisors is an integer number (6521544187566).
Almost surely, 213043088375131 is an apocalyptic number.
13043088375131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13043088375131 is an equidigital number, since it uses as much as digits as its factorization.
13043088375131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 725760, while the sum is 47.
The spelling of 13043088375131 in words is "thirteen trillion, forty-three billion, eighty-eight million, three hundred seventy-five thousand, one hundred thirty-one".
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