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130431244222841 is a prime number
BaseRepresentation
bin11101101010000001100011…
…111110101100000101111001
3122002211002211200002122000012
4131222001203332230011321
5114043441142010112331
61141223141510151305
736321226552133252
oct3552014376540571
9562732750078005
10130431244222841
11386176420346a1
1212766547952535
1357a17c8c94743
14242cc97b2bb29
151012c38e3e82b
hex76a063fac179

130431244222841 has 2 divisors, whose sum is σ = 130431244222842. Its totient is φ = 130431244222840.

The previous prime is 130431244222789. The next prime is 130431244222879. The reversal of 130431244222841 is 148222442134031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81504422880400 + 48926821342441 = 9027980^2 + 6994771^2 .

It is a cyclic number.

It is not a de Polignac number, because 130431244222841 - 26 = 130431244222777 is a prime.

It is a super-2 number, since 2×1304312442228412 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130431244222241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65215622111420 + 65215622111421.

It is an arithmetic number, because the mean of its divisors is an integer number (65215622111421).

Almost surely, 2130431244222841 is an apocalyptic number.

It is an amenable number.

130431244222841 is a deficient number, since it is larger than the sum of its proper divisors (1).

130431244222841 is an equidigital number, since it uses as much as digits as its factorization.

130431244222841 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 294912, while the sum is 41.

Adding to 130431244222841 its reverse (148222442134031), we get a palindrome (278653686356872).

The spelling of 130431244222841 in words is "one hundred thirty trillion, four hundred thirty-one billion, two hundred forty-four million, two hundred twenty-two thousand, eight hundred forty-one".