Base | Representation |
---|---|
bin | 11101101010000010101010… |
… | …111001010101110101100101 |
3 | 122002211012220120212201222011 |
4 | 131222002222321111311211 |
5 | 114044001111101101201 |
6 | 1141223455531234221 |
7 | 36321301210116043 |
oct | 3552025271256545 |
9 | 562735816781864 |
10 | 130432434003301 |
11 | 386180a26a0331 |
12 | 1276681a2a8971 |
13 | 57a195861b451 |
14 | 242cd6bb5b393 |
15 | 1012ca860c151 |
hex | 76a0aae55d65 |
130432434003301 has 16 divisors (see below), whose sum is σ = 135735974809344. Its totient is φ = 125234776016064.
The previous prime is 130432434003299. The next prime is 130432434003329. The reversal of 130432434003301 is 103300434234031.
It is a cyclic number.
It is not a de Polignac number, because 130432434003301 - 21 = 130432434003299 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130432434403301) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19630975 + ... + 25421251.
It is an arithmetic number, because the mean of its divisors is an integer number (8483498425584).
Almost surely, 2130432434003301 is an apocalyptic number.
It is an amenable number.
130432434003301 is a deficient number, since it is larger than the sum of its proper divisors (5303540806043).
130432434003301 is an equidigital number, since it uses as much as digits as its factorization.
130432434003301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5799420.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 130432434003301 its reverse (103300434234031), we get a palindrome (233732868237332).
The spelling of 130432434003301 in words is "one hundred thirty trillion, four hundred thirty-two billion, four hundred thirty-four million, three thousand, three hundred one".
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