130434120110137 has 2 divisors, whose sum is σ = 130434120110138. Its totient is φ = 130434120110136.

The previous prime is 130434120110071. The next prime is 130434120110141. The reversal of 130434120110137 is 731011021434031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126938551423401 + 3495568686736 = 11266701^2 + 1869644^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130434120110137 is a prime.

It is a super-2 number, since 2×130434120110137² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130434120110099 and 130434120110108.

It is not a weakly prime, because it can be changed into another prime (130434120113137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65217060055068 + 65217060055069.

It is an arithmetic number, because the mean of its divisors is an integer number (65217060055069).

Almost surely, 2^{130434120110137} is an apocalyptic number.

It is an amenable number.

130434120110137 is a deficient number, since it is larger than the sum of its proper divisors (1).

130434120110137 is an equidigital number, since it uses as much as digits as its factorization.

130434120110137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 130434120110137 its reverse (731011021434031), we get a palindrome (861445141544168).

The spelling of 130434120110137 in words is "one hundred thirty trillion, four hundred thirty-four billion, one hundred twenty million, one hundred ten thousand, one hundred thirty-seven".