130434120117113 has 2 divisors, whose sum is σ = 130434120117114. Its totient is φ = 130434120117112.

The previous prime is 130434120117107. The next prime is 130434120117121. The reversal of 130434120117113 is 311711021434031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 66169960098064 + 64264160019049 = 8134492^2 + 8016493^2 .

It is a cyclic number.

It is not a de Polignac number, because 130434120117113 - 2⁸ = 130434120116857 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 130434120117113.

It is not a weakly prime, because it can be changed into another prime (130434120117173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65217060058556 + 65217060058557.

It is an arithmetic number, because the mean of its divisors is an integer number (65217060058557).

Almost surely, 2^{130434120117113} is an apocalyptic number.

It is an amenable number.

130434120117113 is a deficient number, since it is larger than the sum of its proper divisors (1).

130434120117113 is an equidigital number, since it uses as much as digits as its factorization.

130434120117113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 32.

The spelling of 130434120117113 in words is "one hundred thirty trillion, four hundred thirty-four billion, one hundred twenty million, one hundred seventeen thousand, one hundred thirteen".