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130434219977 is a prime number
BaseRepresentation
bin111100101111001111…
…1000011111111001001
3110110200011222220110012
41321132133003333021
54114112130014402
6135530510001305
712265165401545
oct1713637037711
9413604886405
10130434219977
1150353798016
12213421a6235
13c3b8b37b29
14645501aa25
1535d6036452
hex1e5e7c3fc9

130434219977 has 2 divisors, whose sum is σ = 130434219978. Its totient is φ = 130434219976.

The previous prime is 130434219889. The next prime is 130434220003. The reversal of 130434219977 is 779912434031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99109113856 + 31325106121 = 314816^2 + 176989^2 .

It is a cyclic number.

It is not a de Polignac number, because 130434219977 - 214 = 130434203593 is a prime.

It is a super-3 number, since 3×1304342199773 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (130434219277) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65217109988 + 65217109989.

It is an arithmetic number, because the mean of its divisors is an integer number (65217109989).

Almost surely, 2130434219977 is an apocalyptic number.

It is an amenable number.

130434219977 is a deficient number, since it is larger than the sum of its proper divisors (1).

130434219977 is an equidigital number, since it uses as much as digits as its factorization.

130434219977 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1143072, while the sum is 50.

The spelling of 130434219977 in words is "one hundred thirty billion, four hundred thirty-four million, two hundred nineteen thousand, nine hundred seventy-seven".