Base | Representation |
---|---|
bin | 111100101111001111… |
… | …1000011111111001001 |
3 | 110110200011222220110012 |
4 | 1321132133003333021 |
5 | 4114112130014402 |
6 | 135530510001305 |
7 | 12265165401545 |
oct | 1713637037711 |
9 | 413604886405 |
10 | 130434219977 |
11 | 50353798016 |
12 | 213421a6235 |
13 | c3b8b37b29 |
14 | 645501aa25 |
15 | 35d6036452 |
hex | 1e5e7c3fc9 |
130434219977 has 2 divisors, whose sum is σ = 130434219978. Its totient is φ = 130434219976.
The previous prime is 130434219889. The next prime is 130434220003. The reversal of 130434219977 is 779912434031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 99109113856 + 31325106121 = 314816^2 + 176989^2 .
It is a cyclic number.
It is not a de Polignac number, because 130434219977 - 214 = 130434203593 is a prime.
It is a super-3 number, since 3×1304342199773 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (130434219277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65217109988 + 65217109989.
It is an arithmetic number, because the mean of its divisors is an integer number (65217109989).
Almost surely, 2130434219977 is an apocalyptic number.
It is an amenable number.
130434219977 is a deficient number, since it is larger than the sum of its proper divisors (1).
130434219977 is an equidigital number, since it uses as much as digits as its factorization.
130434219977 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1143072, while the sum is 50.
The spelling of 130434219977 in words is "one hundred thirty billion, four hundred thirty-four million, two hundred nineteen thousand, nine hundred seventy-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.085 sec. • engine limits •