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1304354101481 is a prime number
BaseRepresentation
bin10010111110110001100…
…100000001100011101001
311121200202200100201120222
4102332301210001203221
5132332304122221411
62435113443055425
7163144052633654
oct22766144014351
94550680321528
101304354101481
1146319a982072
12190961671575
13960001a9b52
14471b995689b
1523de12e44db
hex12fb19018e9

1304354101481 has 2 divisors, whose sum is σ = 1304354101482. Its totient is φ = 1304354101480.

The previous prime is 1304354101441. The next prime is 1304354101487. The reversal of 1304354101481 is 1841014534031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 787019153881 + 517334947600 = 887141^2 + 719260^2 .

It is a cyclic number.

It is not a de Polignac number, because 1304354101481 - 222 = 1304349907177 is a prime.

It is a super-2 number, since 2×13043541014812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1304354101487) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652177050740 + 652177050741.

It is an arithmetic number, because the mean of its divisors is an integer number (652177050741).

Almost surely, 21304354101481 is an apocalyptic number.

It is an amenable number.

1304354101481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304354101481 is an equidigital number, since it uses as much as digits as its factorization.

1304354101481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 35.

The spelling of 1304354101481 in words is "one trillion, three hundred four billion, three hundred fifty-four million, one hundred one thousand, four hundred eighty-one".