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13044000011011 = 19686526316369
BaseRepresentation
bin1011110111010000101011…
…1111001011001100000011
31201011222211210021200022221
42331310022333023030003
53202203103000323021
643424155245311511
72514253323463024
oct275641277131403
951158753250287
1013044000011011
114179a24a4a262
121568021265597
137380756643a8
1433149394ac4b
151794873e7241
hexbdd0afcb303

13044000011011 has 4 divisors (see below), whose sum is σ = 13730526327400. Its totient is φ = 12357473694624.

The previous prime is 13044000010997. The next prime is 13044000011017. The reversal of 13044000011011 is 11011000044031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13044000011011 - 213 = 13044000002819 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13044000011017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 343263158166 + ... + 343263158203.

It is an arithmetic number, because the mean of its divisors is an integer number (3432631581850).

Almost surely, 213044000011011 is an apocalyptic number.

13044000011011 is a deficient number, since it is larger than the sum of its proper divisors (686526316389).

13044000011011 is an equidigital number, since it uses as much as digits as its factorization.

13044000011011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 686526316388.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 13044000011011 its reverse (11011000044031), we get a palindrome (24055000055042).

The spelling of 13044000011011 in words is "thirteen trillion, forty-four billion, eleven thousand, eleven".

Divisors: 1 19 686526316369 13044000011011