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130440000323 is a prime number
BaseRepresentation
bin111100101111011010…
…1000111001101000011
3110110200120212120121002
41321132311013031003
54114120120002243
6135531233522215
712265265465063
oct1713665071503
9413616776532
10130440000323
1150356a85966
122134411336b
13c3ba0acb59
146455ac33a3
1535d67c8eb8
hex1e5ed47343

130440000323 has 2 divisors, whose sum is σ = 130440000324. Its totient is φ = 130440000322.

The previous prime is 130440000277. The next prime is 130440000347. The reversal of 130440000323 is 323000044031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130440000323 - 212 = 130439996227 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130440000295 and 130440000304.

It is not a weakly prime, because it can be changed into another prime (130440000373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220000161 + 65220000162.

It is an arithmetic number, because the mean of its divisors is an integer number (65220000162).

Almost surely, 2130440000323 is an apocalyptic number.

130440000323 is a deficient number, since it is larger than the sum of its proper divisors (1).

130440000323 is an equidigital number, since it uses as much as digits as its factorization.

130440000323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 20.

Adding to 130440000323 its reverse (323000044031), we get a palindrome (453440044354).

The spelling of 130440000323 in words is "one hundred thirty billion, four hundred forty million, three hundred twenty-three", and thus it is an aban number.