13044000341041 has 4 divisors (see below), whose sum is σ = 13730526674800. Its totient is φ = 12357474007284.

The previous prime is 13044000341027. The next prime is 13044000341059. The reversal of 13044000341041 is 14014300044031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13044000341041 - 2²⁷ = 13043866123313 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13044000340997 and 13044000341015.

It is not an unprimeable number, because it can be changed into a prime (13044000341741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 343263166851 + ... + 343263166888.

It is an arithmetic number, because the mean of its divisors is an integer number (3432631668700).

Almost surely, 2^{13044000341041} is an apocalyptic number.

It is an amenable number.

13044000341041 is a deficient number, since it is larger than the sum of its proper divisors (686526333759).

13044000341041 is an equidigital number, since it uses as much as digits as its factorization.

13044000341041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 686526333758.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13044000341041 its reverse (14014300044031), we get a palindrome (27058300385072).

The spelling of 13044000341041 in words is "thirteen trillion, forty-four billion, three hundred forty-one thousand, forty-one".