Base | Representation |
---|---|
bin | 11000010010111101… |
… | …11010011100001011 |
3 | 1020200001120212211111 |
4 | 30021132322130023 |
5 | 203203231004043 |
6 | 5554202111151 |
7 | 641146114021 |
oct | 141136723413 |
9 | 36601525744 |
10 | 13044000523 |
11 | 5593aa8724 |
12 | 26404ab4b7 |
13 | 12cb539408 |
14 | 8ba540711 |
15 | 51524409d |
hex | 3097ba70b |
13044000523 has 2 divisors, whose sum is σ = 13044000524. Its totient is φ = 13044000522.
The previous prime is 13044000503. The next prime is 13044000527. The reversal of 13044000523 is 32500044031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13044000523 - 225 = 13010446091 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13044000494 and 13044000503.
It is not a weakly prime, because it can be changed into another prime (13044000527) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522000261 + 6522000262.
It is an arithmetic number, because the mean of its divisors is an integer number (6522000262).
Almost surely, 213044000523 is an apocalyptic number.
13044000523 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044000523 is an equidigital number, since it uses as much as digits as its factorization.
13044000523 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 22.
Adding to 13044000523 its reverse (32500044031), we get a palindrome (45544044554).
The spelling of 13044000523 in words is "thirteen billion, forty-four million, five hundred twenty-three", and thus it is an aban number.
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