Base | Representation |
---|---|
bin | 11101101010001001101110… |
… | …100101001001001001000011 |
3 | 122002211221110201020100221211 |
4 | 131222021232211021021003 |
5 | 114044112121033310201 |
6 | 1141231151514230551 |
7 | 36321660045114142 |
oct | 3552115645111103 |
9 | 562757421210854 |
10 | 130440012010051 |
11 | 38620331240a27 |
12 | 12768194125457 |
13 | 57a25955bc503 |
14 | 242d48a377759 |
15 | 101309da4c651 |
hex | 76a26e949243 |
130440012010051 has 2 divisors, whose sum is σ = 130440012010052. Its totient is φ = 130440012010050.
The previous prime is 130440012009973. The next prime is 130440012010103. The reversal of 130440012010051 is 150010210044031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130440012010051 - 211 = 130440012008003 is a prime.
It is not a weakly prime, because it can be changed into another prime (130440012010751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220006005025 + 65220006005026.
It is an arithmetic number, because the mean of its divisors is an integer number (65220006005026).
Almost surely, 2130440012010051 is an apocalyptic number.
130440012010051 is a deficient number, since it is larger than the sum of its proper divisors (1).
130440012010051 is an equidigital number, since it uses as much as digits as its factorization.
130440012010051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 480, while the sum is 22.
Adding to 130440012010051 its reverse (150010210044031), we get a palindrome (280450222054082).
The spelling of 130440012010051 in words is "one hundred thirty trillion, four hundred forty billion, twelve million, ten thousand, fifty-one".
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