Base | Representation |
---|---|
bin | 11101101010001001101110… |
… | …100101001100010011101001 |
3 | 122002211221110201021000202001 |
4 | 131222021232211030103221 |
5 | 114044112121034214032 |
6 | 1141231151514411001 |
7 | 36321660045200014 |
oct | 3552115645142351 |
9 | 562757421230661 |
10 | 130440012023017 |
11 | 3862033124a744 |
12 | 12768194130a61 |
13 | 57a25955c5398 |
14 | 242d48a37c37b |
15 | 101309da513e7 |
hex | 76a26e94c4e9 |
130440012023017 has 2 divisors, whose sum is σ = 130440012023018. Its totient is φ = 130440012023016.
The previous prime is 130440012022927. The next prime is 130440012023023. The reversal of 130440012023017 is 710320210044031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 130297910165721 + 142101857296 = 11414811^2 + 376964^2 .
It is an emirp because it is prime and its reverse (710320210044031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130440012023017 - 243 = 121643919000809 is a prime.
It is not a weakly prime, because it can be changed into another prime (130440012053017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220006011508 + 65220006011509.
It is an arithmetic number, because the mean of its divisors is an integer number (65220006011509).
Almost surely, 2130440012023017 is an apocalyptic number.
It is an amenable number.
130440012023017 is a deficient number, since it is larger than the sum of its proper divisors (1).
130440012023017 is an equidigital number, since it uses as much as digits as its factorization.
130440012023017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 130440012023017 its reverse (710320210044031), we get a palindrome (840760222067048).
The spelling of 130440012023017 in words is "one hundred thirty trillion, four hundred forty billion, twelve million, twenty-three thousand, seventeen".
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