Base | Representation |
---|---|
bin | 11000010010111101… |
… | …11010110011011011 |
3 | 1020200001120221212121 |
4 | 30021132322303123 |
5 | 203203231031021 |
6 | 5554202122111 |
7 | 641146121245 |
oct | 141136726333 |
9 | 36601527777 |
10 | 13044002011 |
11 | 5593aa9857 |
12 | 26404b0337 |
13 | 12cb539cb1 |
14 | 8ba541095 |
15 | 515244741 |
hex | 3097bacdb |
13044002011 has 2 divisors, whose sum is σ = 13044002012. Its totient is φ = 13044002010.
The previous prime is 13044001973. The next prime is 13044002047. The reversal of 13044002011 is 11020044031.
It is a strong prime.
It is an emirp because it is prime and its reverse (11020044031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13044002011 - 223 = 13035613403 is a prime.
It is not a weakly prime, because it can be changed into another prime (13044402011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522001005 + 6522001006.
It is an arithmetic number, because the mean of its divisors is an integer number (6522001006).
Almost surely, 213044002011 is an apocalyptic number.
13044002011 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044002011 is an equidigital number, since it uses as much as digits as its factorization.
13044002011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 13044002011 its reverse (11020044031), we get a palindrome (24064046042).
The spelling of 13044002011 in words is "thirteen billion, forty-four million, two thousand, eleven".
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