Base | Representation |
---|---|
bin | 11101101010001001101111… |
… | …010100100001101010001011 |
3 | 122002211221111120121102121222 |
4 | 131222021233110201222023 |
5 | 114044112132223244433 |
6 | 1141231153040352255 |
7 | 36321660255516422 |
oct | 3552115724415213 |
9 | 562757446542558 |
10 | 130440024431243 |
11 | 3862033825517a |
12 | 1276819831568b |
13 | 57a259804b127 |
14 | 242d48bc8c2b9 |
15 | 101309eba2b98 |
hex | 76a26f521a8b |
130440024431243 has 2 divisors, whose sum is σ = 130440024431244. Its totient is φ = 130440024431242.
The previous prime is 130440024431237. The next prime is 130440024431257. The reversal of 130440024431243 is 342134420044031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130440024431243 - 26 = 130440024431179 is a prime.
It is not a weakly prime, because it can be changed into another prime (130440024431273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220012215621 + 65220012215622.
It is an arithmetic number, because the mean of its divisors is an integer number (65220012215622).
Almost surely, 2130440024431243 is an apocalyptic number.
130440024431243 is a deficient number, since it is larger than the sum of its proper divisors (1).
130440024431243 is an equidigital number, since it uses as much as digits as its factorization.
130440024431243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 130440024431243 its reverse (342134420044031), we get a palindrome (472574444475274).
The spelling of 130440024431243 in words is "one hundred thirty trillion, four hundred forty billion, twenty-four million, four hundred thirty-one thousand, two hundred forty-three".
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