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1304402053103 = 192231987154937
BaseRepresentation
bin10010111110110100011…
…010111100011111101111
311121200220000120220211222
4102332310122330133233
5132332403411144403
62435122314533555
7163145204340422
oct22766432743757
94550800526758
101304402053103
11463214a53906
121909757372bb
139600a0c8aa6
14471c20799b9
1523de5617338
hex12fb46bc7ef

1304402053103 has 16 divisors (see below), whose sum is σ = 1379915013120. Its totient is φ = 1229580772416.

The previous prime is 1304402053099. The next prime is 1304402053127. The reversal of 1304402053103 is 3013502044031.

It is a cyclic number.

It is not a de Polignac number, because 1304402053103 - 22 = 1304402053099 is a prime.

It is a super-3 number, since 3×13044020531033 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1304402053183) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8341451 + ... + 8496387.

It is an arithmetic number, because the mean of its divisors is an integer number (86244688320).

Almost surely, 21304402053103 is an apocalyptic number.

1304402053103 is a deficient number, since it is larger than the sum of its proper divisors (75512960017).

1304402053103 is a wasteful number, since it uses less digits than its factorization.

1304402053103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 157166.

The product of its (nonzero) digits is 4320, while the sum is 26.

Adding to 1304402053103 its reverse (3013502044031), we get a palindrome (4317904097134).

The spelling of 1304402053103 in words is "one trillion, three hundred four billion, four hundred two million, fifty-three thousand, one hundred three".

Divisors: 1 19 223 1987 4237 37753 154937 443101 2943803 8418919 34550951 307859819 656468069 5849336561 68652739637 1304402053103