Base | Representation |
---|---|
bin | 10010111110110100011… |
… | …010111100011111101111 |
3 | 11121200220000120220211222 |
4 | 102332310122330133233 |
5 | 132332403411144403 |
6 | 2435122314533555 |
7 | 163145204340422 |
oct | 22766432743757 |
9 | 4550800526758 |
10 | 1304402053103 |
11 | 463214a53906 |
12 | 1909757372bb |
13 | 9600a0c8aa6 |
14 | 471c20799b9 |
15 | 23de5617338 |
hex | 12fb46bc7ef |
1304402053103 has 16 divisors (see below), whose sum is σ = 1379915013120. Its totient is φ = 1229580772416.
The previous prime is 1304402053099. The next prime is 1304402053127. The reversal of 1304402053103 is 3013502044031.
It is a cyclic number.
It is not a de Polignac number, because 1304402053103 - 22 = 1304402053099 is a prime.
It is a super-3 number, since 3×13044020531033 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1304402053183) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8341451 + ... + 8496387.
It is an arithmetic number, because the mean of its divisors is an integer number (86244688320).
Almost surely, 21304402053103 is an apocalyptic number.
1304402053103 is a deficient number, since it is larger than the sum of its proper divisors (75512960017).
1304402053103 is a wasteful number, since it uses less digits than its factorization.
1304402053103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 157166.
The product of its (nonzero) digits is 4320, while the sum is 26.
Adding to 1304402053103 its reverse (3013502044031), we get a palindrome (4317904097134).
The spelling of 1304402053103 in words is "one trillion, three hundred four billion, four hundred two million, fifty-three thousand, one hundred three".
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