Base | Representation |
---|---|
bin | 1011110111010000110001… |
… | …0100100101010110001001 |
3 | 1201011222220100102011210022 |
4 | 2331310030110211112021 |
5 | 3202203124213303033 |
6 | 43424201405230225 |
7 | 2514254015003135 |
oct | 275641424452611 |
9 | 51158810364708 |
10 | 13044022400393 |
11 | 4179a36651786 |
12 | 1568028862375 |
13 | 73807a1a324a |
14 | 3314968d83c5 |
15 | 17948936b098 |
hex | bdd0c525589 |
13044022400393 has 2 divisors, whose sum is σ = 13044022400394. Its totient is φ = 13044022400392.
The previous prime is 13044022400377. The next prime is 13044022400417. The reversal of 13044022400393 is 39300422044031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12899217036304 + 144805364089 = 3591548^2 + 380533^2 .
It is an emirp because it is prime and its reverse (39300422044031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13044022400393 - 24 = 13044022400377 is a prime.
It is not a weakly prime, because it can be changed into another prime (13044022400693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522011200196 + 6522011200197.
It is an arithmetic number, because the mean of its divisors is an integer number (6522011200197).
Almost surely, 213044022400393 is an apocalyptic number.
It is an amenable number.
13044022400393 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044022400393 is an equidigital number, since it uses as much as digits as its factorization.
13044022400393 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 35.
The spelling of 13044022400393 in words is "thirteen trillion, forty-four billion, twenty-two million, four hundred thousand, three hundred ninety-three".
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