Base | Representation |
---|---|
bin | 11000010010111101… |
… | …11111110100010011 |
3 | 1020200001122000001012 |
4 | 30021132333310103 |
5 | 203203232210142 |
6 | 5554202401135 |
7 | 641146235153 |
oct | 141136776423 |
9 | 36601560035 |
10 | 13044022547 |
11 | 5594013226 |
12 | 26405001ab |
13 | 12cb54644a |
14 | 8ba548763 |
15 | 51524a882 |
hex | 3097bfd13 |
13044022547 has 2 divisors, whose sum is σ = 13044022548. Its totient is φ = 13044022546.
The previous prime is 13044022507. The next prime is 13044022561. The reversal of 13044022547 is 74522044031.
It is a strong prime.
It is an emirp because it is prime and its reverse (74522044031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13044022547 - 26 = 13044022483 is a prime.
It is not a weakly prime, because it can be changed into another prime (13044022507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522011273 + 6522011274.
It is an arithmetic number, because the mean of its divisors is an integer number (6522011274).
Almost surely, 213044022547 is an apocalyptic number.
13044022547 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044022547 is an equidigital number, since it uses as much as digits as its factorization.
13044022547 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26880, while the sum is 32.
Adding to 13044022547 its reverse (74522044031), we get a palindrome (87566066578).
The spelling of 13044022547 in words is "thirteen billion, forty-four million, twenty-two thousand, five hundred forty-seven".
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