13044034113113 has 4 divisors (see below), whose sum is σ = 13048885002420. Its totient is φ = 13039183223808.

The previous prime is 13044034113107. The next prime is 13044034113119. The reversal of 13044034113113 is 31131143044031.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13044034113107) and next prime (13044034113119).

It can be written as a sum of positive squares in 2 ways, for example, as 1358828513344 + 11685205599769 = 1165688^2 + 3418363^2 .

It is a cyclic number.

It is not a de Polignac number, because 13044034113113 - 2¹² = 13044034109017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13044034113119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2425440620 + ... + 2425445997.

It is an arithmetic number, because the mean of its divisors is an integer number (3262221250605).

Almost surely, 2^{13044034113113} is an apocalyptic number.

It is an amenable number.

13044034113113 is a deficient number, since it is larger than the sum of its proper divisors (4850889307).

13044034113113 is an equidigital number, since it uses as much as digits as its factorization.

13044034113113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4850889306.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 13044034113113 its reverse (31131143044031), we get a palindrome (44175177157144).

The spelling of 13044034113113 in words is "thirteen trillion, forty-four billion, thirty-four million, one hundred thirteen thousand, one hundred thirteen".