Base | Representation |
---|---|
bin | 1011110111010000110101… |
… | …1100101011100000110110 |
3 | 1201011222221122222101012120 |
4 | 2331310031130223200312 |
5 | 3202203144033100042 |
6 | 43424203322300410 |
7 | 2514254334440115 |
oct | 275641534534066 |
9 | 51158848871176 |
10 | 13044041300022 |
11 | 4179a46290307 |
12 | 1568033057706 |
13 | 73808108c865 |
14 | 331499217c7c |
15 | 17948ad50dec |
hex | bdd0d72b836 |
13044041300022 has 64 divisors (see below), whose sum is σ = 26512276976640. Its totient is φ = 4277851167744.
The previous prime is 13044041299963. The next prime is 13044041300027. The reversal of 13044041300022 is 22000314044031.
It is a junction number, because it is equal to n+sod(n) for n = 13044041299965 and 13044041300001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13044041300027) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 90446823 + ... + 90590925.
It is an arithmetic number, because the mean of its divisors is an integer number (414254327760).
Almost surely, 213044041300022 is an apocalyptic number.
13044041300022 is an abundant number, since it is smaller than the sum of its proper divisors (13468235676618).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13044041300022 is a wasteful number, since it uses less digits than its factorization.
13044041300022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 145037.
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 13044041300022 its reverse (22000314044031), we get a palindrome (35044355344053).
The spelling of 13044041300022 in words is "thirteen trillion, forty-four billion, forty-one million, three hundred thousand, twenty-two".
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