130440424441 has 2 divisors, whose sum is σ = 130440424442. Its totient is φ = 130440424440.

The previous prime is 130440424381. The next prime is 130440424463. The reversal of 130440424441 is 144424044031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95805725625 + 34634698816 = 309525^2 + 186104^2 .

It is an emirp because it is prime and its reverse (144424044031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130440424441 - 2⁹ = 130440423929 is a prime.

It is not a weakly prime, because it can be changed into another prime (130440425441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220212220 + 65220212221.

It is an arithmetic number, because the mean of its divisors is an integer number (65220212221).

Almost surely, 2^130440424441 is an apocalyptic number.

It is an amenable number.

130440424441 is a deficient number, since it is larger than the sum of its proper divisors (1).

130440424441 is an equidigital number, since it uses as much as digits as its factorization.

130440424441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24576, while the sum is 31.

Adding to 130440424441 its reverse (144424044031), we get a palindrome (274864468472).

The spelling of 130440424441 in words is "one hundred thirty billion, four hundred forty million, four hundred twenty-four thousand, four hundred forty-one".