130441003310001 has 4 divisors (see below), whose sum is σ = 173921337746672. Its totient is φ = 86960668873332.

The previous prime is 130441003309973. The next prime is 130441003310011. The reversal of 130441003310001 is 100013300144031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 130441003310001 - 2¹⁰ = 130441003308977 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 130441003310001.

It is not an unprimeable number, because it can be changed into a prime (130441003310011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21740167218331 + ... + 21740167218336.

It is an arithmetic number, because the mean of its divisors is an integer number (43480334436668).

Almost surely, 2^{130441003310001} is an apocalyptic number.

It is an amenable number.

130441003310001 is a deficient number, since it is larger than the sum of its proper divisors (43480334436671).

130441003310001 is an equidigital number, since it uses as much as digits as its factorization.

130441003310001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43480334436670.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 130441003310001 its reverse (100013300144031), we get a palindrome (230454303454032).

The spelling of 130441003310001 in words is "one hundred thirty trillion, four hundred forty-one billion, three million, three hundred ten thousand, one".