Base | Representation |
---|---|
bin | 11101101010001010101010… |
… | …010100001100011011011111 |
3 | 122002212001001120000220011020 |
4 | 131222022222110030123133 |
5 | 114044121144113400111 |
6 | 1141231435154455223 |
7 | 36322023634435623 |
oct | 3552125224143337 |
9 | 562761046026136 |
10 | 130441014200031 |
11 | 386207a5a20107 |
12 | 12768413894513 |
13 | 57a26c5115432 |
14 | 242d5434d5183 |
15 | 101310ba12906 |
hex | 76a2aa50c6df |
130441014200031 has 16 divisors (see below), whose sum is σ = 174016184494080. Its totient is φ = 86913261784800.
The previous prime is 130441014199961. The next prime is 130441014200053. The reversal of 130441014200031 is 130002410144031.
It is not a de Polignac number, because 130441014200031 - 215 = 130441014167263 is a prime.
It is a super-2 number, since 2×1304410142000312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130441014199974 and 130441014200010.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130441014200531) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 343946610 + ... + 344325648.
It is an arithmetic number, because the mean of its divisors is an integer number (10876011530880).
Almost surely, 2130441014200031 is an apocalyptic number.
130441014200031 is a deficient number, since it is larger than the sum of its proper divisors (43575170294049).
130441014200031 is a wasteful number, since it uses less digits than its factorization.
130441014200031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 441286.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 130441014200031 its reverse (130002410144031), we get a palindrome (260443424344062).
The spelling of 130441014200031 in words is "one hundred thirty trillion, four hundred forty-one billion, fourteen million, two hundred thousand, thirty-one".
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