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13044112234521 = 34348037411507
BaseRepresentation
bin1011110111010001000110…
…1011010001100000011001
31201012000010121110020001020
42331310101223101200121
53202203320213001041
643424214334513053
72514256155405204
oct275642153214031
951160117406036
1013044112234521
114179a8232a465
121568052965789
13738092997834
143314a480093b
151794921b3866
hexbdd11ad1819

13044112234521 has 4 divisors (see below), whose sum is σ = 17392149646032. Its totient is φ = 8696074823012.

The previous prime is 13044112234501. The next prime is 13044112234523. The reversal of 13044112234521 is 12543221144031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13044112234521 - 27 = 13044112234393 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13044112234523) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2174018705751 + ... + 2174018705756.

It is an arithmetic number, because the mean of its divisors is an integer number (4348037411508).

Almost surely, 213044112234521 is an apocalyptic number.

It is an amenable number.

13044112234521 is a deficient number, since it is larger than the sum of its proper divisors (4348037411511).

13044112234521 is an equidigital number, since it uses as much as digits as its factorization.

13044112234521 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4348037411510.

The product of its (nonzero) digits is 23040, while the sum is 33.

Adding to 13044112234521 its reverse (12543221144031), we get a palindrome (25587333378552).

The spelling of 13044112234521 in words is "thirteen trillion, forty-four billion, one hundred twelve million, two hundred thirty-four thousand, five hundred twenty-one".

Divisors: 1 3 4348037411507 13044112234521