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130441333130323 = 331394082577433
BaseRepresentation
bin11101101010001010111101…
…010100110100010001010011
3122002212001212210011020021021
4131222022331110310101103
5114044122322240132243
61141231530550340311
736322034556340555
oct3552127524642123
9562761783136237
10130441333130323
1138620949a54166
12127684a265a697
1357a2746210797
14242d5739d54d5
151013129a106ed
hex76a2bd534453

130441333130323 has 4 divisors (see below), whose sum is σ = 130835415708088. Its totient is φ = 130047250552560.

The previous prime is 130441333130291. The next prime is 130441333130443. The reversal of 130441333130323 is 323031333144031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130441333130323 - 25 = 130441333130291 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130441333131323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 197041288386 + ... + 197041289047.

It is an arithmetic number, because the mean of its divisors is an integer number (32708853927022).

Almost surely, 2130441333130323 is an apocalyptic number.

130441333130323 is a deficient number, since it is larger than the sum of its proper divisors (394082577765).

130441333130323 is an equidigital number, since it uses as much as digits as its factorization.

130441333130323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 394082577764.

The product of its (nonzero) digits is 69984, while the sum is 34.

Adding to 130441333130323 its reverse (323031333144031), we get a palindrome (453472666274354).

The spelling of 130441333130323 in words is "one hundred thirty trillion, four hundred forty-one billion, three hundred thirty-three million, one hundred thirty thousand, three hundred twenty-three".

Divisors: 1 331 394082577433 130441333130323