Base | Representation |
---|---|
bin | 1011110111010001011011… |
… | …1010100111001010000011 |
3 | 1201012000100201212100200011 |
4 | 2331310112322213022003 |
5 | 3202204010214011233 |
6 | 43424231155005351 |
7 | 2514261303532462 |
oct | 275642672471203 |
9 | 51160321770604 |
10 | 13044200141443 |
11 | 417a017a11209 |
12 | 1568078299857 |
13 | 7380a7c65b73 |
14 | 3314b23649d9 |
15 | 179499c7a0cd |
hex | bdd16ea7283 |
13044200141443 has 2 divisors, whose sum is σ = 13044200141444. Its totient is φ = 13044200141442.
The previous prime is 13044200141303. The next prime is 13044200141449. The reversal of 13044200141443 is 34414100244031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13044200141443 is a prime.
It is a super-2 number, since 2×130442001414432 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13044200141449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522100070721 + 6522100070722.
It is an arithmetic number, because the mean of its divisors is an integer number (6522100070722).
Almost surely, 213044200141443 is an apocalyptic number.
13044200141443 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044200141443 is an equidigital number, since it uses as much as digits as its factorization.
13044200141443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 13044200141443 its reverse (34414100244031), we get a palindrome (47458300385474).
The spelling of 13044200141443 in words is "thirteen trillion, forty-four billion, two hundred million, one hundred forty-one thousand, four hundred forty-three".
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