Base | Representation |
---|---|
bin | 111100101111011110… |
… | …1010010000110101001 |
3 | 110110200201220101120221 |
4 | 1321132331102012221 |
5 | 4114121142021441 |
6 | 135531351450041 |
7 | 12265322625304 |
oct | 1713675220651 |
9 | 413621811527 |
10 | 130442142121 |
11 | 50358209045 |
12 | 21344986921 |
13 | c3ba67c9a5 |
14 | 64560bdb3b |
15 | 35d6a9d8d1 |
hex | 1e5ef521a9 |
130442142121 has 2 divisors, whose sum is σ = 130442142122. Its totient is φ = 130442142120.
The previous prime is 130442142113. The next prime is 130442142143. The reversal of 130442142121 is 121241244031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 103722643600 + 26719498521 = 322060^2 + 163461^2 .
It is an emirp because it is prime and its reverse (121241244031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130442142121 - 23 = 130442142113 is a prime.
It is a super-2 number, since 2×1304421421212 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130442142191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65221071060 + 65221071061.
It is an arithmetic number, because the mean of its divisors is an integer number (65221071061).
Almost surely, 2130442142121 is an apocalyptic number.
It is an amenable number.
130442142121 is a deficient number, since it is larger than the sum of its proper divisors (1).
130442142121 is an equidigital number, since it uses as much as digits as its factorization.
130442142121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 130442142121 its reverse (121241244031), we get a palindrome (251683386152).
The spelling of 130442142121 in words is "one hundred thirty billion, four hundred forty-two million, one hundred forty-two thousand, one hundred twenty-one".
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