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13044224311342 = 27933073998561
BaseRepresentation
bin1011110111010001100001…
…0110110100000000101110
31201012000102102100022112121
42331310120112310000232
53202204032410430332
643424233421023154
72514262016136610
oct275643026640056
951160372308477
1013044224311342
11417a02a61a434
1215680843b4aba
137380acc79293
143314b5656db0
1517949be51797
hexbdd185b402e

13044224311342 has 16 divisors (see below), whose sum is σ = 22361573750112. Its totient is φ = 5590370257920.

The previous prime is 13044224311319. The next prime is 13044224311343. The reversal of 13044224311342 is 24311342244031.

It is a junction number, because it is equal to n+sod(n) for n = 13044224311298 and 13044224311307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044224311343) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12563742 + ... + 13562302.

It is an arithmetic number, because the mean of its divisors is an integer number (1397598359382).

Almost surely, 213044224311342 is an apocalyptic number.

13044224311342 is a deficient number, since it is larger than the sum of its proper divisors (9317349438770).

13044224311342 is an equidigital number, since it uses as much as digits as its factorization.

13044224311342 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1931643.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 13044224311342 its reverse (24311342244031), we get a palindrome (37355566555373).

The spelling of 13044224311342 in words is "thirteen trillion, forty-four billion, two hundred twenty-four million, three hundred eleven thousand, three hundred forty-two".

Divisors: 1 2 7 14 933073 998561 1866146 1997122 6531511 6989927 13063022 13979854 931730307953 1863460615906 6522112155671 13044224311342