Base | Representation |
---|---|
bin | 1011110111010001100011… |
… | …0001110111101010101001 |
3 | 1201012000102220200200010002 |
4 | 2331310120301313222221 |
5 | 3202204041214413301 |
6 | 43424234233032345 |
7 | 2514262133340524 |
oct | 275643061675251 |
9 | 51160386620102 |
10 | 13044231404201 |
11 | 417a0336243a8 |
12 | 15680868556b5 |
13 | 7380b159083a |
14 | 3314b6581bbb |
15 | 17949c8a316b |
hex | bdd18c77aa9 |
13044231404201 has 2 divisors, whose sum is σ = 13044231404202. Its totient is φ = 13044231404200.
The previous prime is 13044231404173. The next prime is 13044231404213. The reversal of 13044231404201 is 10240413244031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12266448517801 + 777782886400 = 3502349^2 + 881920^2 .
It is a cyclic number.
It is not a de Polignac number, because 13044231404201 - 242 = 8646184893097 is a prime.
It is not a weakly prime, because it can be changed into another prime (13044231404261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522115702100 + 6522115702101.
It is an arithmetic number, because the mean of its divisors is an integer number (6522115702101).
Almost surely, 213044231404201 is an apocalyptic number.
It is an amenable number.
13044231404201 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044231404201 is an equidigital number, since it uses as much as digits as its factorization.
13044231404201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 13044231404201 its reverse (10240413244031), we get a palindrome (23284644648232).
The spelling of 13044231404201 in words is "thirteen trillion, forty-four billion, two hundred thirty-one million, four hundred four thousand, two hundred one".
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