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130442314324121 is a prime number
BaseRepresentation
bin11101101010001011110111…
…110011110001100010011001
3122002212011102011110001010022
4131222023313303301202121
5114044131324431332441
61141232212201000225
736322101102344102
oct3552136763614231
9562764364401108
10130442314324121
11386213028a2628
1212768717183075
1357a2871594a27
14242d6280493a9
151013185c2984b
hex76a2f7cf1899

130442314324121 has 2 divisors, whose sum is σ = 130442314324122. Its totient is φ = 130442314324120.

The previous prime is 130442314324079. The next prime is 130442314324169. The reversal of 130442314324121 is 121423413244031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 89674536272896 + 40767778051225 = 9469664^2 + 6384965^2 .

It is a cyclic number.

It is not a de Polignac number, because 130442314324121 - 230 = 130441240582297 is a prime.

It is not a weakly prime, because it can be changed into another prime (130442314324181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65221157162060 + 65221157162061.

It is an arithmetic number, because the mean of its divisors is an integer number (65221157162061).

Almost surely, 2130442314324121 is an apocalyptic number.

It is an amenable number.

130442314324121 is a deficient number, since it is larger than the sum of its proper divisors (1).

130442314324121 is an equidigital number, since it uses as much as digits as its factorization.

130442314324121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 130442314324121 its reverse (121423413244031), we get a palindrome (251865727568152).

The spelling of 130442314324121 in words is "one hundred thirty trillion, four hundred forty-two billion, three hundred fourteen million, three hundred twenty-four thousand, one hundred twenty-one".