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1304424033617 is a prime number
BaseRepresentation
bin10010111110110101101…
…110110010110101010001
311121200221112221122110002
4102332311232302311101
5132332430023033432
62435124422015345
7163145562225515
oct22766556626521
94550845848402
101304424033617
114632263a7121
12190980b77555
1396011823803
14471c4d5c145
1523de7509e62
hex12fb5bb2d51

1304424033617 has 2 divisors, whose sum is σ = 1304424033618. Its totient is φ = 1304424033616.

The previous prime is 1304424033461. The next prime is 1304424033643. The reversal of 1304424033617 is 7163304244031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1057614787216 + 246809246401 = 1028404^2 + 496799^2 .

It is a cyclic number.

It is not a de Polignac number, because 1304424033617 - 236 = 1235704556881 is a prime.

It is a super-2 number, since 2×13044240336172 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1304424093617) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652212016808 + 652212016809.

It is an arithmetic number, because the mean of its divisors is an integer number (652212016809).

Almost surely, 21304424033617 is an apocalyptic number.

It is an amenable number.

1304424033617 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304424033617 is an equidigital number, since it uses as much as digits as its factorization.

1304424033617 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145152, while the sum is 38.

Adding to 1304424033617 its reverse (7163304244031), we get a palindrome (8467728277648).

The spelling of 1304424033617 in words is "one trillion, three hundred four billion, four hundred twenty-four million, thirty-three thousand, six hundred seventeen".