Base | Representation |
---|---|
bin | 10010111110110101101… |
… | …110110101011011101011 |
3 | 11121200221112222012001112 |
4 | 102332311232311123223 |
5 | 132332430023404032 |
6 | 2435124422140535 |
7 | 163145562301541 |
oct | 22766556653353 |
9 | 4550845865045 |
10 | 1304424044267 |
11 | 463226404123 |
12 | 190980b8174b |
13 | 96011828606 |
14 | 471c4d61d91 |
15 | 23de750d1b2 |
hex | 12fb5bb56eb |
1304424044267 has 2 divisors, whose sum is σ = 1304424044268. Its totient is φ = 1304424044266.
The previous prime is 1304424044239. The next prime is 1304424044281. The reversal of 1304424044267 is 7624404244031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1304424044267 - 210 = 1304424043243 is a prime.
It is not a weakly prime, because it can be changed into another prime (1304424044467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652212022133 + 652212022134.
It is an arithmetic number, because the mean of its divisors is an integer number (652212022134).
Almost surely, 21304424044267 is an apocalyptic number.
1304424044267 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304424044267 is an equidigital number, since it uses as much as digits as its factorization.
1304424044267 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 516096, while the sum is 41.
Adding to 1304424044267 its reverse (7624404244031), we get a palindrome (8928828288298).
The spelling of 1304424044267 in words is "one trillion, three hundred four billion, four hundred twenty-four million, forty-four thousand, two hundred sixty-seven".
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