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13044240990233 is a prime number
BaseRepresentation
bin1011110111010001100101…
…0110011100000000011001
31201012000110120201200200022
42331310121112130000121
53202204101143141413
643424235214320225
72514262310664245
oct275643126340031
951160416650608
1013044240990233
11417a038a81542
121568089ab9075
137380b3568b4b
143314b7959425
1517949d648608
hexbdd1959c019

13044240990233 has 2 divisors, whose sum is σ = 13044240990234. Its totient is φ = 13044240990232.

The previous prime is 13044240990223. The next prime is 13044240990257. The reversal of 13044240990233 is 33209904244031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9523075058704 + 3521165931529 = 3085948^2 + 1876477^2 .

It is an emirp because it is prime and its reverse (33209904244031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13044240990233 - 28 = 13044240989977 is a prime.

It is a super-2 number, since 2×130442409902332 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13044240990203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522120495116 + 6522120495117.

It is an arithmetic number, because the mean of its divisors is an integer number (6522120495117).

Almost surely, 213044240990233 is an apocalyptic number.

It is an amenable number.

13044240990233 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044240990233 is an equidigital number, since it uses as much as digits as its factorization.

13044240990233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 559872, while the sum is 44.

The spelling of 13044240990233 in words is "thirteen trillion, forty-four billion, two hundred forty million, nine hundred ninety thousand, two hundred thirty-three".