Base | Representation |
---|---|
bin | 111100101111011111… |
… | …0101101001001011011 |
3 | 110110200202121100010120 |
4 | 1321132332231021123 |
5 | 4114121240440120 |
6 | 135531403444323 |
7 | 12265326040440 |
oct | 1713676551133 |
9 | 413622540116 |
10 | 130442515035 |
11 | 50358443238 |
12 | 21344b266a3 |
13 | c3ba780651 |
14 | 64561799c7 |
15 | 35d6b24140 |
hex | 1e5efad25b |
130442515035 has 16 divisors (see below), whose sum is σ = 238523456256. Its totient is φ = 59630863968.
The previous prime is 130442514997. The next prime is 130442515039. The reversal of 130442515035 is 530515244031.
It is not a de Polignac number, because 130442515035 - 26 = 130442514971 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130442514987 and 130442515005.
It is not an unprimeable number, because it can be changed into a prime (130442515039) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 621154729 + ... + 621154938.
It is an arithmetic number, because the mean of its divisors is an integer number (14907716016).
Almost surely, 2130442515035 is an apocalyptic number.
130442515035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
130442515035 is a deficient number, since it is larger than the sum of its proper divisors (108080941221).
130442515035 is a wasteful number, since it uses less digits than its factorization.
130442515035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1242309682.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 130442515035 its reverse (530515244031), we get a palindrome (660957759066).
The spelling of 130442515035 in words is "one hundred thirty billion, four hundred forty-two million, five hundred fifteen thousand, thirty-five".
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