1304430055051 has 2 divisors, whose sum is σ = 1304430055052. Its totient is φ = 1304430055050.

The previous prime is 1304430055013. The next prime is 1304430055067. The reversal of 1304430055051 is 1505500344031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1304430055051 - 2⁹ = 1304430054539 is a prime.

It is a super-2 number, since 2×1304430055051² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1304430055091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652215027525 + 652215027526.

It is an arithmetic number, because the mean of its divisors is an integer number (652215027526).

Almost surely, 2^{1304430055051} is an apocalyptic number.

1304430055051 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304430055051 is an equidigital number, since it uses as much as digits as its factorization.

1304430055051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 1304430055051 its reverse (1505500344031), we get a palindrome (2809930399082).

The spelling of 1304430055051 in words is "one trillion, three hundred four billion, four hundred thirty million, fifty-five thousand, fifty-one".