Base | Representation |
---|---|
bin | 10010111110110110001… |
… | …010010010010000001001 |
3 | 11121200222001111210000121 |
4 | 102332312022102100021 |
5 | 132332433344141301 |
6 | 2435125240303241 |
7 | 163146010412125 |
oct | 22766612222011 |
9 | 4550861453017 |
10 | 1304431240201 |
11 | 46322a479581 |
12 | 190983471b21 |
13 | 96013177a6b |
14 | 471c5cb6585 |
15 | 23de7e803a1 |
hex | 12fb6292409 |
1304431240201 has 2 divisors, whose sum is σ = 1304431240202. Its totient is φ = 1304431240200.
The previous prime is 1304431240183. The next prime is 1304431240253. The reversal of 1304431240201 is 1020421344031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1288454280201 + 15976960000 = 1135101^2 + 126400^2 .
It is a cyclic number.
It is not a de Polignac number, because 1304431240201 - 237 = 1166992286729 is a prime.
It is not a weakly prime, because it can be changed into another prime (1304431240261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652215620100 + 652215620101.
It is an arithmetic number, because the mean of its divisors is an integer number (652215620101).
Almost surely, 21304431240201 is an apocalyptic number.
It is an amenable number.
1304431240201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304431240201 is an equidigital number, since it uses as much as digits as its factorization.
1304431240201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1304431240201 its reverse (1020421344031), we get a palindrome (2324852584232).
The spelling of 1304431240201 in words is "one trillion, three hundred four billion, four hundred thirty-one million, two hundred forty thousand, two hundred one".
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