1304431514113 has 16 divisors (see below), whose sum is σ = 1606245652480. Its totient is φ = 1031568872256.

The previous prime is 1304431514039. The next prime is 1304431514117. The reversal of 1304431514113 is 3114151344031.

It is not a de Polignac number, because 1304431514113 - 2¹³ = 1304431505921 is a prime.

It is a super-3 number, since 3×1304431514113³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (1304431514117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3347745 + ... + 3717022.

It is an arithmetic number, because the mean of its divisors is an integer number (100390353280).

Almost surely, 2^{1304431514113} is an apocalyptic number.

1304431514113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1304431514113 is a deficient number, since it is larger than the sum of its proper divisors (301814138367).

1304431514113 is a wasteful number, since it uses less digits than its factorization.

1304431514113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7066816.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 1304431514113 its reverse (3114151344031), we get a palindrome (4418582858144).

The spelling of 1304431514113 in words is "one trillion, three hundred four billion, four hundred thirty-one million, five hundred fourteen thousand, one hundred thirteen".