Base | Representation |
---|---|
bin | 10010111110110110010… |
… | …010010110010100011011 |
3 | 11121200222012111011121212 |
4 | 102332312102112110123 |
5 | 132332434414312021 |
6 | 2435125353453335 |
7 | 163146034364624 |
oct | 22766622262433 |
9 | 4550865434555 |
10 | 1304433354011 |
11 | 463230692727 |
12 | 19098411124b |
13 | 96013737c38 |
14 | 471c62a6a4b |
15 | 23de824b85b |
hex | 12fb649651b |
1304433354011 has 2 divisors, whose sum is σ = 1304433354012. Its totient is φ = 1304433354010.
The previous prime is 1304433353957. The next prime is 1304433354017. The reversal of 1304433354011 is 1104533344031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1304433354011 is a prime.
It is not a weakly prime, because it can be changed into another prime (1304433354017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652216677005 + 652216677006.
It is an arithmetic number, because the mean of its divisors is an integer number (652216677006).
Almost surely, 21304433354011 is an apocalyptic number.
1304433354011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304433354011 is an equidigital number, since it uses as much as digits as its factorization.
1304433354011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 1304433354011 its reverse (1104533344031), we get a palindrome (2408966698042).
The spelling of 1304433354011 in words is "one trillion, three hundred four billion, four hundred thirty-three million, three hundred fifty-four thousand, eleven".
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