Base | Representation |
---|---|
bin | 11000010011000000… |
… | …01101010110011010 |
3 | 1020200002020010200020 |
4 | 30021200031112122 |
5 | 203203322340442 |
6 | 5554213251310 |
7 | 641152030062 |
oct | 141140152632 |
9 | 36602203606 |
10 | 13044340122 |
11 | 559420a890 |
12 | 2640633b36 |
13 | 12cb627b68 |
14 | 8ba5cc3a2 |
15 | 5152ae9ec |
hex | 30980d59a |
13044340122 has 32 divisors (see below), whose sum is σ = 28472822784. Its totient is φ = 3951102000.
The previous prime is 13044340079. The next prime is 13044340151. The reversal of 13044340122 is 22104344031.
It is a junction number, because it is equal to n+sod(n) for n = 13044340092 and 13044340101.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 113133 + ... + 197199.
It is an arithmetic number, because the mean of its divisors is an integer number (889775712).
Almost surely, 213044340122 is an apocalyptic number.
13044340122 is an abundant number, since it is smaller than the sum of its proper divisors (15428482662).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13044340122 is a wasteful number, since it uses less digits than its factorization.
13044340122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 86434.
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 13044340122 its reverse (22104344031), we get a palindrome (35148684153).
The spelling of 13044340122 in words is "thirteen billion, forty-four million, three hundred forty thousand, one hundred twenty-two".
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