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130443432000353 is a prime number
BaseRepresentation
bin11101101010001100111010…
…011011010111101101100001
3122002212021022001112212200022
4131222030322123113231201
5114044141122043002403
61141232515124403225
736322140563420303
oct3552147233275541
9562767261485608
10130443432000353
113862182679029a
1212768989546515
1357a29bbcc4204
14242d6d2669973
1510131ede02d38
hex76a33a6d7b61

130443432000353 has 2 divisors, whose sum is σ = 130443432000354. Its totient is φ = 130443432000352.

The previous prime is 130443432000317. The next prime is 130443432000361. The reversal of 130443432000353 is 353000234344031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104805341552704 + 25638090447649 = 10237448^2 + 5063407^2 .

It is a cyclic number.

It is not a de Polignac number, because 130443432000353 - 26 = 130443432000289 is a prime.

It is not a weakly prime, because it can be changed into another prime (130443432000953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65221716000176 + 65221716000177.

It is an arithmetic number, because the mean of its divisors is an integer number (65221716000177).

Almost surely, 2130443432000353 is an apocalyptic number.

It is an amenable number.

130443432000353 is a deficient number, since it is larger than the sum of its proper divisors (1).

130443432000353 is an equidigital number, since it uses as much as digits as its factorization.

130443432000353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 35.

Adding to 130443432000353 its reverse (353000234344031), we get a palindrome (483443666344384).

The spelling of 130443432000353 in words is "one hundred thirty trillion, four hundred forty-three billion, four hundred thirty-two million, three hundred fifty-three", and thus it is an aban number.