13044431110041 has 6 divisors (see below), whose sum is σ = 18841956047850. Its totient is φ = 8696287406688.

The previous prime is 13044431110021. The next prime is 13044431110091. The reversal of 13044431110041 is 14001113444031.

13044431110041 is a `hidden beast` number, since 1 + 304 + 4 + 4 + 311 + 1 + 0 + 0 + 41 = 666.

It can be written as a sum of positive squares in only one way, i.e., 6749370182025 + 6295060928016 = 2597955^2 + 2508996^2 .

It is not a de Polignac number, because 13044431110041 - 2⁶ = 13044431109977 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13044431109987 and 13044431110014.

It is not an unprimeable number, because it can be changed into a prime (13044431110021) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 724690617216 + ... + 724690617233.

It is an arithmetic number, because the mean of its divisors is an integer number (3140326007975).

Almost surely, 2^{13044431110041} is an apocalyptic number.

It is an amenable number.

13044431110041 is a deficient number, since it is larger than the sum of its proper divisors (5797524937809).

13044431110041 is a wasteful number, since it uses less digits than its factorization.

13044431110041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1449381234455 (or 1449381234452 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 13044431110041 its reverse (14001113444031), we get a palindrome (27045544554072).

The spelling of 13044431110041 in words is "thirteen trillion, forty-four billion, four hundred thirty-one million, one hundred ten thousand, forty-one".