Base | Representation |
---|---|
bin | 10010111110111011001… |
… | …011111010110011111001 |
3 | 11121201011221011101120101 |
4 | 102332323023322303321 |
5 | 132333121440221203 |
6 | 2435141451355401 |
7 | 163151053154431 |
oct | 22767313726371 |
9 | 4551157141511 |
10 | 1304515554553 |
11 | 463273027162 |
12 | 1909a7752b61 |
13 | 96027788b03 |
14 | 471d31832c1 |
15 | 23e0058741d |
hex | 12fbb2facf9 |
1304515554553 has 4 divisors (see below), whose sum is σ = 1304687593728. Its totient is φ = 1304343515380.
The previous prime is 1304515554523. The next prime is 1304515554557. The reversal of 1304515554553 is 3554555154031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1304515554553 - 237 = 1167076601081 is a prime.
It is a super-2 number, since 2×13045155545532 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1304515554557) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86008213 + ... + 86023378.
It is an arithmetic number, because the mean of its divisors is an integer number (326171898432).
Almost surely, 21304515554553 is an apocalyptic number.
It is an amenable number.
1304515554553 is a deficient number, since it is larger than the sum of its proper divisors (172039175).
1304515554553 is an equidigital number, since it uses as much as digits as its factorization.
1304515554553 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 172039174.
The product of its (nonzero) digits is 2250000, while the sum is 46.
The spelling of 1304515554553 in words is "one trillion, three hundred four billion, five hundred fifteen million, five hundred fifty-four thousand, five hundred fifty-three".
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