Base | Representation |
---|---|
bin | 1011110111011000001011… |
… | …0111101011111101110010 |
3 | 1201012012000221220110101111 |
4 | 2331312002313223331302 |
5 | 3202221212344022114 |
6 | 43425131014423534 |
7 | 2514354215332156 |
oct | 275660267537562 |
9 | 51165027813344 |
10 | 13046011314034 |
11 | 417a867306a66 |
12 | 15684a2961baa |
13 | 73830626841a |
14 | 331604b09066 |
15 | 179553c8dbc4 |
hex | bdd82debf72 |
13046011314034 has 8 divisors (see below), whose sum is σ = 19593882306288. Its totient is φ = 6514717211940.
The previous prime is 13046011313983. The next prime is 13046011314047. The reversal of 13046011314034 is 43041311064031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×130460113140342 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13046011313987 and 13046011314005.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4144220572 + ... + 4144223719.
It is an arithmetic number, because the mean of its divisors is an integer number (2449235288286).
Almost surely, 213046011314034 is an apocalyptic number.
13046011314034 is a deficient number, since it is larger than the sum of its proper divisors (6547870992254).
13046011314034 is an equidigital number, since it uses as much as digits as its factorization.
13046011314034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8288445080.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 13046011314034 its reverse (43041311064031), we get a palindrome (56087322378065).
The spelling of 13046011314034 in words is "thirteen trillion, forty-six billion, eleven million, three hundred fourteen thousand, thirty-four".
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