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13046011314034 = 27878288444291
BaseRepresentation
bin1011110111011000001011…
…0111101011111101110010
31201012012000221220110101111
42331312002313223331302
53202221212344022114
643425131014423534
72514354215332156
oct275660267537562
951165027813344
1013046011314034
11417a867306a66
1215684a2961baa
1373830626841a
14331604b09066
15179553c8dbc4
hexbdd82debf72

13046011314034 has 8 divisors (see below), whose sum is σ = 19593882306288. Its totient is φ = 6514717211940.

The previous prime is 13046011313983. The next prime is 13046011314047. The reversal of 13046011314034 is 43041311064031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×130460113140342 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13046011313987 and 13046011314005.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4144220572 + ... + 4144223719.

It is an arithmetic number, because the mean of its divisors is an integer number (2449235288286).

Almost surely, 213046011314034 is an apocalyptic number.

13046011314034 is a deficient number, since it is larger than the sum of its proper divisors (6547870992254).

13046011314034 is an equidigital number, since it uses as much as digits as its factorization.

13046011314034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8288445080.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 13046011314034 its reverse (43041311064031), we get a palindrome (56087322378065).

The spelling of 13046011314034 in words is "thirteen trillion, forty-six billion, eleven million, three hundred fourteen thousand, thirty-four".

Divisors: 1 2 787 1574 8288444291 16576888582 6523005657017 13046011314034