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130475015421203 = 891466011409227
BaseRepresentation
bin11101101010101010010100…
…111100100011110100010011
3122002222021211011022220010002
4131222222110330203310103
5114100200312421434303
61141255221123000215
736324336341155415
oct3552522474436423
9562867734286102
10130475015421203
11386341638018a2
1212772b2280906b
1357a5983438a0b
14243104b0d09b5
151013e4ba53788
hex76aa94f23d13

130475015421203 has 4 divisors (see below), whose sum is σ = 131941026830520. Its totient is φ = 129009004011888.

The previous prime is 130475015421199. The next prime is 130475015421209. The reversal of 130475015421203 is 302124510574031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130475015421203 - 22 = 130475015421199 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130475015421209) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 733005704525 + ... + 733005704702.

It is an arithmetic number, because the mean of its divisors is an integer number (32985256707630).

Almost surely, 2130475015421203 is an apocalyptic number.

130475015421203 is a deficient number, since it is larger than the sum of its proper divisors (1466011409317).

130475015421203 is an equidigital number, since it uses as much as digits as its factorization.

130475015421203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1466011409316.

The product of its (nonzero) digits is 100800, while the sum is 38.

Adding to 130475015421203 its reverse (302124510574031), we get a palindrome (432599525995234).

The spelling of 130475015421203 in words is "one hundred thirty trillion, four hundred seventy-five billion, fifteen million, four hundred twenty-one thousand, two hundred three".

Divisors: 1 89 1466011409227 130475015421203