Search a number
-
+
13048593554281 is a prime number
BaseRepresentation
bin1011110111100001110011…
…0010001001101101101001
31201012102200220211212002011
42331320130302021231221
53202242004422214111
643430235141035521
72514505212114325
oct275703462115551
951172626755064
1013048593554281
11418097198130a
121568aa36b5ba1
1373862823082c
143317aba46985
15179655812021
hexbde1cc89b69

13048593554281 has 2 divisors, whose sum is σ = 13048593554282. Its totient is φ = 13048593554280.

The previous prime is 13048593554273. The next prime is 13048593554327. The reversal of 13048593554281 is 18245539584031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12637911240256 + 410682314025 = 3554984^2 + 640845^2 .

It is a cyclic number.

It is not a de Polignac number, because 13048593554281 - 23 = 13048593554273 is a prime.

It is a super-2 number, since 2×130485935542812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13048593554221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6524296777140 + 6524296777141.

It is an arithmetic number, because the mean of its divisors is an integer number (6524296777141).

Almost surely, 213048593554281 is an apocalyptic number.

It is an amenable number.

13048593554281 is a deficient number, since it is larger than the sum of its proper divisors (1).

13048593554281 is an equidigital number, since it uses as much as digits as its factorization.

13048593554281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736000, while the sum is 58.

The spelling of 13048593554281 in words is "thirteen trillion, forty-eight billion, five hundred ninety-three million, five hundred fifty-four thousand, two hundred eighty-one".